the lenght of a rectangle is 5meter greater than it's width . If the perimeter of the rectangle is 50meter find it's lenght
Answers
SOLUTION:-
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Given:
•The length of a rectangle is 5m greater than it's width.
•If the perimeter of rectangle is 50m
To find:
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It's length.
Explanation:
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Let the width of the rectangle be R m
Let the length of the rectangle be R+5 m
- Perimeter= 50m
According to the question:
We know that, perimeter of rectangle;
=) 2[length + width]
Therefore,
=) 2[R+5 + R] = 50
=) 2[2R +5]= 50
=) 4R + 10 = 50
=) 4R =50 -10
=) 4R= 40
=) R = 40/4
=) R= 10m
Thus,
Length of the rectangle= R+5
=) [10 +5]m
=) 15m
:)
Given:
- The length of a rectangle is 5m greater than it's width.
- If the perimeter of rectangle is 50m
To find:
- Length of the rectangle =?
Step-by-step explanation :
Perimeter of the rectangle = 50 cm [Given]
Let the width of the rectangle be x m
Then, the length of the rectangle be x + 5 m
We know that,
Perimeter of rectangle = 2(length + breadth)
Substituting the values in the above formula, we get,
➟ 2(x+5 + x) = 50
➟ 2(2x +5) = 50
➟ 4x + 10 = 50
➟ 4x = 50 -10
➟ 4x = 40
➟ x = 40/4
➟ x = 10
Therefore, We know that the value of x = 10.
Hence,
Length of the rectangle = x + 5
= 10 + 5
= 15.
Therefore, The length of the rectangle = 15 cm.