The lenght of a rectangle is 6cm more than it's breadth . If the perimeter of a rectangle is 68cm , find the lenght and breadth of the rectangle
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Let i and w be the length and width of the rectangle. We are given:
l = w + 6
2(l+w) = 60
You have two equations and two unknowns. Solving for l and w gives l = 18 and w = 12. Whence, the area A is given by
A = l \cdot w = (18)(12) = 216 cm^2
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