Question

the lenght of a rectangle is 8m less than twice its breadth. if the perimeter of the rectangle is 56m. find its dimensions.

Answer 1

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Answer 2

length = l
breadth = b
l = 2b - 8 {given}
perimeter = 56m
2[l+b] = 56m
l+b = 56\2 = 28
2b - 8 + b = 28
3b = 28 + 8 = 36
b = 36\3 = 12
then l = 24 - 8 = 16