the lenght of a rectangular sign is 3 times witdh if the signs perimeteris 32 incheswhat is the signs area
Answers
Answered by
20
Answer:
48 inch^2
Step-by-step explanation:
Let the width be a and thus length should be 3 times of a.
So,
Width is a and length is 3a.
Given,
Perimeter of that rectangular structure is 32 inch.
⇒ 2( length + breadth ) = 32 inch
⇒ 2( a + 3a ) = 32 inch
⇒ 2( 4a ) = 32 inch
⇒ 8a = 32 inch
⇒ a = 4 inch
Area of that figure is length x breadth
⇒ a x 3a
⇒ 3a^2
⇒ 3( 4 inch )^2
⇒ 3 x 16 inch^2
⇒ 48 inch^2
Answered by
20
Step-by-step explanation:
Aloha !
perimeter=32 inches
2(a+b)=32
2(a+3a)=32
2(4a)=32
4a=16
a=4 inches.
Area= a×b
=a×3a
=4×3(4)
=4×12
=48 inches ²
Thank you
@ Twilight Astro ✌️☺️♥️
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