Math, asked by 47515, 8 months ago

the lenght of a rectangular sign is 3 times witdh if the signs perimeteris 32 incheswhat is the signs area

Answers

Answered by abhi569
20

Answer:

48 inch^2

Step-by-step explanation:

Let the width be a and thus length should be 3 times of a.

So,

     Width is a and length is 3a.

Given,

      Perimeter of that rectangular structure is 32 inch.

⇒ 2( length + breadth ) = 32 inch

⇒ 2( a + 3a ) = 32 inch

⇒ 2( 4a ) = 32 inch

⇒ 8a = 32 inch

⇒ a = 4 inch

      Area of that figure is length x breadth

            ⇒ a x 3a

            ⇒ 3a^2

            ⇒ 3( 4 inch )^2

            ⇒ 3 x 16 inch^2

            ⇒ 48 inch^2

Answered by saivivek16
20

Step-by-step explanation:

Aloha !

perimeter=32 inches

2(a+b)=32

2(a+3a)=32

2(4a)=32

4a=16

a=4 inches.

Area= a×b

=a×3a

=4×3(4)

=4×12

=48 inches ²

Thank you

@ Twilight Astro ✌️☺️♥️

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