the lenght of minute hand of a clock is 14cm. the area swept by the minute hand in 5 minutes is :a)153.9cm^2 (b)102.6cm^2 (c) 51.3cm^2 and (d)205.2cm^2
Answers
We have to find the area swept by the minute hand of a clock which is 14 cm long in 5 minutes.
We know, The minute hand will turn 360° in one hour, and one hour is equal to 60 minutes.
∴ In 60 minutes, the minute hand turns 360°. So in one minute It would turn,
⇒ In 1 minute, it would turn 360/60 × 5
⇒ Angle, θ = 6 × 5
⇒ Angle, θ = 30°
So, In 5 minutes, the minute hand would turn 30°.
Imagine the clock as a circle of radius the length of the minute hand, so In that hypothetical circle, we have
- Radius of circle, r = 14 cm
- Angle, θ = 30°
Now, This is a sector and we have to find the area of this sector. So
⇒ Area of sector = πr²θ/360°
⇒ Area = 22/7 × 14 × 14 × 30/360
⇒ Area = 44 × 14 × 1/12
⇒ Area = 11 × 14 × 1/3
⇒ Area = 154 / 3
⇒ Area = 51.3 cm²
Hence, In 5 minutes, the area swept by the minute hand of length 14 cm is 51.3 cm².
∴ Option (C) is correct.
Answer
We know, The minute hand will turn 360° in one hour, and one hour is equal to 60 minutes.
∴ In 60 minutes, the minute hand turns 360°. So in one minute It would turn,
- Imagine the clock as a circle of radius the length of the minute hand, so In that hypothetical circle, we have
Radius of circle, r = 14 cm
Angle, θ = 30°
Now, This is a sector and we have to find the area of this sector. So
✒ Area of sector = πr²θ/360°
✒ Area = 22/7 × 14 × 14 × 30/360
✒ Area = 44 × 14 × 1/12
✒ Area = 11 × 14 × 1/3
✒ Area = 154 / 3
✒ Area = 51.3 cm²
- Hence, In 5 minutes, the area swept by the minute hand of length 14 cm is 51.3 cm².
- ∴ Option (C) is correct.