The lenght of rectangle is 20m more than it's width. If the perimeter of the of the rectangle is 100m,then find the length breath of rectangle.
Answers
Given: the length of the rectangle is 20m more than its width. If the perimeter of the rectangle is 100m.
To find: breath of rectangle
Solution:
let the Width be x metres
length= 20+x
perimeter= 2(l+b)
100 = 2(x+x+20)
50 = 20+2x
50/2= 10+x
25= 10+ x
x= 25-10= 15 metres
length = 20+15= 35 metres
The length of the rectangle = 35 metres and the width of the rectangle is 15 metres.
Given that:
Lenth of the rectangle= 20m + width
Perimeter of the rectangle= 100m
To find:
Length L and Width W/breadth B
Solution:
We can find the lenth and width/breadth of the rectangle by using the simple formula of perimeter of rectangle i.e. 2(length+breadth)
let the width of the rectangle be X
given that the length is 20m more than the width hence L = X + 20
now perimeter P = 2x(Length + Breadth)
= 2 x ( X + 20 + X)
= 2 x (2X + 20)
= 4X + 80
now perimeter is 100 metres
=> 100 = 4X + 80
=> 20 = 4X
=> X = 5m
We get breadth by,
Equation for Lenth of the rectangle =
4X + 80m(metre)
Where breadth = 5m (metre)
We get the value of length of rectangle by putting the value of breadth=5m
Length=20+X
=20+5
=25 m(metre)
Therefore the lenth and breadth of the rectangle with perimeter 100m is 25m and 5m respectively.