Question

The lenght omand breadth of a rectangular field are in ratio 4 is to 3 its area is 6912m sq find the cost of fencing the field at ruppes 2.50 per meter

Answer 1

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$\underline{SOLUTION}$ ➡

$Given, \\ \\ Area \: of \: the \: rectangular \: field \: = 6912 \: sq.m \\ \\ Ratio \: of \: length \: and \: breadth \: of \: the \: rectangular\\ \:field \: = 4 : 3$

$Let, \\ \\ Length \: of \: the \: rectangular \: field \: = 4x \: \: m \\ \\ Breadth \: of \: the \: rectangular \: field \: = 3x\: \: m$

$A.T.Q., \\ \\ 4x \times 3x = 6912 \\ \\ = > 12x {}^{2} = 6912 \\ \\ = > x {}^{2} = \frac{6912}{12} \\ \\ = > x {}^{2} = 576 \\ \\ = > x = \sqrt{576} \\ \\ = > x = 24$

$So, \\ \\ Length \: of \: the \: rectangular \: field \: = 4x \: \: m \\ \\ =( 4 \times 24) \: \: m\\ \\ = 96 \: \: m \\ \\ \\ Breadth \: of \: the \: rectangular \: field \: = 3x \: \: m\\ \\ = (3 \times 24) \: \: m \\ \\ = 72 \: \: m$
$Now ,\\ \\ Perimeter \: of \: the \: rectangular \: field \: = 2(96 + 72) \: \: m \\ \\ = 2 \times 168 \: \: m\\ \\ = 336 \: \: m \\ \\ \\ Given ,\\ \\ Cost \: of \: fencing \: per \: metre \: = \: Rs.2.50 \\ \\ So, \: cost \: of \: fencing \: 336 \: metre \: = Rs.(2.50 \times 336) \\ \\ = Rs \: .840$

$\underline{ANSWER}$ ➡ $Rs \: .840$

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