the lenghth of sides of a triangle are 35,54 and 61 cms. Find the length of its longest altitude
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Answer:
A=hbb
2
A=s(s﹣a)(s﹣b)(s﹣c)
s=a+b+c
2
Solving forhb
hb=﹣a4+2(ab)2+2(ac)2﹣b4+2(bc)2﹣c4
2b=﹣354+2·(35·54)2+2·(35·61)2﹣544+2·(54·61)2﹣614
2·54≈34.78328
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