Question

The length (16 cm) and area of cross section
(4 cm²) of a copper wire are increased by 25% each.
If the resistance of original wire is 8 S2, find the new
resistance.​

Answer 1

Solution :

(i)`Rpropl//A`

(ii) ` (R_(1))/(R_(2))=(l_(1))/(l_(2))xx(A_(2))/(A_(1))`

(iii)`l_(2)=l_(1)+0.25l_(2)`

`A_(2)=A_(1)+0.25A_(1)`

(iv)`8 Omega`

Answer 2

Answer:

see attachment

Explanation:

see photofor full answer in detail