THE LENGTH & BREADTH OF A RECTANGULAR BASKETBALL COURT ARE IN THE RATIO 9: 5. IF THE AREA OF THE COURT IS 14580 sq. m AND RATE OF FENCING IS Rs. 6.50 ,FIND THE ...
LENGTH OF THE COURT
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Answer:
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Step-by-step explanation:
SOLUTION :
The length and breadth of a rectangle are in ratio = 9:5 respectively (given)
The area of the rectangular field = 14580 m sq. (given)
To be found :-
The cost fencing the field at Rs 3.25 per m
The fencing is done on the perimeter of the rectangular field
Let
length of the rectangular field be 9x m
breadth of the rectangular field be 5x m
Area of the rectangular field = lb unit sq.
[ In which l is the length and b is the breadth of the rectangular field ]
⇒ 14580 = 9x*5x
⇒ 14580 =
⇒ 14580 ÷ 45 = [Transporting 45 to LHS ]
⇒ 324 =
⇒ = x
⇒ 18 = x
∴ Value of x is 18
Now,
length of the rectangular field be 9x m = 9*18 = 162 m
breadth of the rectangular field be 5x m = 5*18 = 90 m
Now,
Perimeter of the rectangular field = 2(l+b) units
[ In which l is the length and b is the breadth of the rectangular field ]
= 2(162 + 90) m
= 2 × 252
= 504 m
So,
If the cost of fencing 1 m = Rs 3.25
Than the cost for fencing the rectangular field will be
= 3.25 × 504
= Rs 1638
Hence,
The cost of fencing the rectangular field is Rs 1638
Answer:
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