The length and breadht if s ractanguler park are in the ratio 5:2 .a wide path of 2.5 metre that runs all around the park has an area 445sq.m find the dimension of the park
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hey here,
the length and breadth of the park = 5x and 2x
area of inside park = 5x * 2x = 10x²
length of outside park = 5x + 2 * 2.5 = 5x + 5
breadth of the outside park = 2x + 2 * 2.5 = 2x + 5
area of outside park = ( 5x + 5 ) ( 2x + 5 )
= 10x² + 25x + 10x + 25
= 10x² + 35x + 25
area of path = area of inside park - area of outside park
445 = 10x² - 10x² + 35x + 25
445 = 35x + 25
35x = 445 - 25
35x = 420
x = 12
length = 12 * 5 = 60
breadth = 12 * 2 = 24
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the length and breadth of the park = 5x and 2x
area of inside park = 5x * 2x = 10x²
length of outside park = 5x + 2 * 2.5 = 5x + 5
breadth of the outside park = 2x + 2 * 2.5 = 2x + 5
area of outside park = ( 5x + 5 ) ( 2x + 5 )
= 10x² + 25x + 10x + 25
= 10x² + 35x + 25
area of path = area of inside park - area of outside park
445 = 10x² - 10x² + 35x + 25
445 = 35x + 25
35x = 445 - 25
35x = 420
x = 12
length = 12 * 5 = 60
breadth = 12 * 2 = 24
HOPE ITS HELP YOU
PLEASE MARK ME BRAINLIST
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