Question

The length and breadth
an rectangle
2l²-5lm + 3n2 units
and 4l² + 2 lm-2n² units. Find
its perimeter​

Answer 1

Answer:

given,

Length = 2l²-5lm + 3n2

Breadth = 4l² + 2 lm-2n² units

perimeter = 2(Length + breadth)

          = 2(2l²-5lm + $3n^{2}$+ 4l² + 2 lm-2n²)

          = 2(6l²-3lm + $n^{2}$ )

Hence, Perimeter = 12 l²- 6lm + $2n^{2}$