the length and breadth and height of a cubiod are (log 125+log8), (log1000-log10) and log 10 respectively. find the total surface area of the cubiod
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Answer:
22 units sq
Step-by-step explanation:
l=log125+log8
Use the product property of
logb(x)+logb(y)=logb(xy)
log(125⋅8)
Multiply 125 by 8.
log(1000)
Logarithm base 10 of 1000 is 3.
therefore l=3
b=log1000 -log 10
use logarithm property of
logb(x)- log b(y)=log b(x/y)
log1000/10
log100
logarithm base 10 of 100 is2.
therefore b=2
h=log 10 =1
TSA of cuboid=2(lb+bh+lh)
=2[(3×2)+(2×1)+(3×1)]
=2(6+2+3)
= 2(11)
=22 units sq
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