The length and breadth of a cardboard are 2 1/5m and 1 1/5m respectively. The length and breadth of a second cardboard are 3 1/5m and 2 2/5m respectively. Both cardboards are divided into 10 equal small pieces. What is the total area of a cardboard,if it is made using 5 smaller pieces from the first cardboard and 3 smaller pieces from the second cardboard?
Answers
Step-by-step explanation:
453/125 square meter.
Step-by-step explanation:
Area of first cardboard =11/5 mx 6/5m
= 66/25 square meter
Area of cardboard divided into 10 equal parts
66/25÷10
33/125square meter
If it is made using 5 smaller pieces from fist cardboard
=33/125 x 5
=33/25 square meter
Area of second cardboard=16/5 m x 12/5m
192/25 square meter
Area of second cardboard also divided in 10 equal parts
192/25÷10
96/125 square meter
If it is made using 3 smaller pieces from the second cardboard
=96/125 x 3
=288/125 square meter
Total area of the first and second cardboard
=33/25 square meter + 288/125 squre meter
=(165 + 288)/125
453/125 square meter
Given:
- The length and breadth of cardboard are 2 1/5m and 1 1/5m respectively.
- The length and breadth of the second cardboard are 3 1/5m and 2 2/5m respectively.
To find:
The total area of cardboard, if it is made using 5 smaller pieces from the first cardboard and 3 smaller pieces from the second cardboard.
Solution:
1) The area of the first cardboard is
- Area = L×B
- =11/5×6/5
- = 66/25
If the cardboard is divided into 10 equal parts so the area of one cardboard is
- 66/(25×10)
- 33/125
2)The area of the second cardboard is
- Area = L×B
- =16/5×12/5
- =192/25
If the cardboard is divided into 10 equal parts so the area of one cardboard is
- 192/(25×10)
- 96/125
3) If the cardboard is made using 5 smaller pieces from the first cardboard and 3 smaller pieces from the second cardboard
- Area = (33/125)×5 + (96/125)×3
- = 165/125 + 288/125
- = 453/125