the length and breadth of a field are 16m 17cm and 22m 77cm respectively.Obtain the maximum length of the rope which can measure the dimensions of the field in exact number of times
Answers
Answered by
9
16m 17cm = 1617 cm
22m and 77 cm = 2277 cm
1617 = 3 × 7 × 7 × 11
2277 = 3 × 3 × 11 × 23
so, H.C.F of 1617 cm and 2277 cm = 33 cm
so, maximum length of the rope = 33 cm
22m and 77 cm = 2277 cm
1617 = 3 × 7 × 7 × 11
2277 = 3 × 3 × 11 × 23
so, H.C.F of 1617 cm and 2277 cm = 33 cm
so, maximum length of the rope = 33 cm
Answered by
5
Solution
Given
Length of a field =16m17cm=1617cm
Breadth of a field=22m77cm=2277cm
Now,
Using Euclid's division algorithm, we get,
2277=1617x1+660
1617=660x2+297
660=297x2+66
297=66x4+33
66=33x2+0
Since, the remainder is zero, we cannot divide any further.
Therefore, maximum length of the Rope which can measure the dimensions of the field in exact number of times=33cm
Hope it helps you ☺
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