Question

The Length and Breadth of a hall is 20m by 10m . How many tiles of size 50cm × 50 cm are required to pave the floor of the hall ?​

Answer 1

$\huge \star{\underline{\mathtt{\red{A}\pink{N} \green{S}\blue{W}\purple{E}\orange{R}}}}\star$

Area of floor = 20×10 m^2

=200 m^2

area of each tile = 2×2 m^2

=4 m^2

no of tiles= (area of floor)/(area of each tile)

= 200/4

= 50 tiles

no of black tiles will be 26 tiles

explanation: the floor is a rectangle.if on the two sides of 20 m there are 20 tiles ( each side 10 tiles) then other two sides of 10 m ,2 tiles will be common on the corners.So, 3 tiles each on sides of 10 m.total tiles = (10×2)+(3×2)

total tiles = 26 tiles

remaining tiles= 50-26

= 24

no of white tiles= 1/3rd of remaining

= 1/3× 24

= 8 tiles

no of blue tiles= 24 - 8

= 16 tiles

Therefore ,there are 16 blue , 8 white and 26 white tiles.

Answer 2

$\large\underline{ \underline{ \sf \maltese{ \: Question:- }}}$

• The Length and Breadth of a hall is 20m by 10m . How many tiles of size 50cm × 50 cm are required to pave the floor of the hall ?

$\large\underline{ \underline{ \sf \maltese{ \: Given:- }}}$

$\red{\boxed{ \sf \blue{ 1Metre \: = \: 100 cm }}}$

• Length of the hall = $\sf\green{ \:20m}$

$\qquad \quad {:} \longrightarrow \sf{\sf{ 20 \: \times \: 100cm }}$

$\bf\therefore\; \fbox{Length \;= 2000cm}$

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• Breadth of the hall = $\sf\green{ \:10m }$

$\qquad \quad {:} \longrightarrow \sf{\sf{ 10 \: \times \: 100cm }}$

$\bf \therefore \;\fbox{ Breadth \;= 1000cm}$

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• Length of Tile = $\sf\green{ </strong><strong>\</strong><strong>:</strong><strong> </strong><strong>5</strong><strong>0</strong><strong>c</strong><strong>m</strong><strong>}$
• Breadth of Tile = $\sf\green{ </strong><strong>\</strong><strong>:</strong><strong> </strong><strong>5</strong><strong>0</strong><strong>c</strong><strong>m</strong><strong>}$

$\quad {:} \longrightarrow \underline \red{\boxed{\sf{Area \: of \: hall \: = \: 2000 \: × \: 1000 }}}$

$\qquad\quad {:} \longrightarrow \underline \red{\boxed{\sf{ Area \:of \:Each \: Tile= 50 × 50 }}}$

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$\large\underline{ \underline{ \sf \maltese{ \: Solution:- }}}$

$\begin{gathered}\begin{gathered}\begin{gathered}: \implies \underline\blue{ \boxed{\displaystyle \sf \bold\orange{\: No.\: of \:Tiles\: Required \: = \: \frac{ Area \: of \: the \: Hall }{Area \: of \: 1 \: Tile} }} }\\ \\\end{gathered}\end{gathered}\end{gathered}$

$\qquad \quad {:} \longrightarrow \sf{\sf{ \frac{2000 \: \times \: 1000}{50 \: \times \: 50} }}$

$\qquad \quad {:} \longrightarrow \sf{\sf{ \frac{2000 \: \times \: 10 \cancel{0}\cancel{0}}{5 \cancel{0} \times \: 5 \cancel{0}} }}$

$\qquad \quad {:} \longrightarrow \sf{\sf{ \frac{\cancel{2000 }\: \times \: \cancel{ 10}}{\cancel{5} \: \times \: \cancel{5}} }}$

$\qquad \quad {:} \longrightarrow \sf{\sf{400 \: \times \: 2} }$

$\qquad\quad {:} \longrightarrow \underline \red{\boxed{\sf{Tiles \: Required\: = \: 800 }}}$

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$\begin{gathered}\begin{gathered}\qquad \therefore\: \sf{ No. \: of \: tiles \: Required \: = \underline {\underline{ 800}}}\\\end{gathered}\end{gathered}$

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More for Knowledge:-

• Area of Rectangle = Length × Breadth
• Length of a Rectangle = Area \ Breadth
• Breadth of a Rectangle = Area \ Length
• Area of Square = side square
• Side of a Square = √Area

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