Question

The length and breadth of a park are 40m and 30m respectively. There is a path 2m
wide outside the park. Find the area of the path.

Answer 1

Answer:

REF.Image

Area of path = (40×2)+(30×2)−(2×2)

{−(2×2) for middle area being

counted twice }

=80+60−4=136m

2

⇒ square files needed =

areaof1tile

Totalarea

=

100

25

×

100

25

136

=136×16=2176

Answer 2

Length of the park = 50 m

Breadth of the park = 30 m

Area of the park = 50×30

=1500m

2

Width of the path inside the park = 2m

Length of the park without path = 50−(2+2)=50−4=46m

Breadth of the park without path = 30−(2+2)=30−4=26m

Area of the park without the path = 46×26

=1196m

2

Area of the path = Area of park - Area of park without path

=1500−1196

=304m

2