The length and breadth of a park are in the ratio 2:1 and its perimeter is 240m A path 2m wide rons inside it , along its boundary Find the cost of paving the path at rupees 80 per metre square
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let length and breadth be 2x and x respectively.
so,2(l+b)=perimeter
=>2*3x=240m
=>x=240/6=40
length=80m , breadth=40m
2m wide path on all the side so,
vol.of outer rectangle-vol. of inner rectangle
=>l*b-(l-2*2m)*(b-2*2m)
=>80*40 - 76*36
=>3200-2736
=>464m^2
cost of paving =464*80
=₹37,120
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so,2(l+b)=perimeter
=>2*3x=240m
=>x=240/6=40
length=80m , breadth=40m
2m wide path on all the side so,
vol.of outer rectangle-vol. of inner rectangle
=>l*b-(l-2*2m)*(b-2*2m)
=>80*40 - 76*36
=>3200-2736
=>464m^2
cost of paving =464*80
=₹37,120
HOPE YOU LIKED IT
PLEASE MARK IT AS BRAINLIEST
IT TOOK A LOT OF EFFORT
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