Question

the length and breadth of a park are in the ratio 2 is to 1 and its perimeter is 240 a part 2 metre wide run inside it along its boundary find the cost of paving the bath at to be ready per metre square​

Answer 1

Step-by-step explanation:

Let us assume the length of the park be 2x Let us assume the breadth of the park be x From the question is given that, Perimeter of the park = 240 m Wide of the path = 2 m Rate of paving the path = ₹ 80 per m2 Then, Perimeter of the park = 2 (l + b) = 240 = 2 (2x + 1x) = 240 = 2 (3x) = 240 = 6x = 240 = x = 240 /6 = x = 40 Then, The length of the park be 2x = 2 × 40 = 80 m The breadth of the park be x = 40 m Let PQRS be the given park and ABCD be the inside boundary of the path. Area of the park PQRS = (l × b) = (80 × 40) = 3200 m2 Wide of the path = 2 m Then, AB = (80 – (2 × 2)) = (80 – 4) = 76 m AD = (40 – (2 × 2)) = (40 – 4) = 36 m ∴Area of the rectangle ABCD = (76 × 36) m2 = 2736 m2 Area of the path = (Area of PQRS – Area of ABCD) = (3200 – 2736) = 464m2 Rate of paving the path = ₹ 80 per m2 ∴Total cost of paving the path of a park = ₹ (80 × 464) = ₹ 37120Read more on Sarthaks.com - https://www.sarthaks.com/753649/the-length-and-breadth-of-park-are-in-the-ratio-and-its-perimeter-is-240-path-wide-runs-inside

Answer 2

I think you forgot to write Find the cost of paving the path at ₹ 80 per m2 ...

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