the length and breadth of a park are in the ratio 3:1 and its perimeter is 320 a path 2 metre wide runs inside it find the cost of paving the birth at rupees 3 square per metre
Answers
The Cost of Paving the path is Rs.1872
The ratio of Length to Breadth of Rectangle = 3 : 1
Perimeter of the Rectangle = 320
Path = 2 m wide
Rate of paving the path = Rs.3 sq.m
The cost of paving the path
First we need to find the measure of the sides.
Consider the Length as 3x
Consider the Breadth as 1x (x)
As We know :
Perimeter of Rectangle =
Value of 3x
3 × 40
120
Length = 120
Breadth = 40
Area of the path = Area of Rectangle including path - Area of the Rectangle excluding path.
Area of the Rectangle including path =
120 × 40
4800
Area of the Rectangle excluding path =
Length = 120 - (2+2)= 116
Breadth = 40 - (2+2) = 36
116 × 36
4176
Area of the path =
4800 - 4176
624
Cost of Paving the path =
624 × 3
1872
The Cost of Paving the path is Rs. 1872
Given,
ratio of length and breadth of a park = 3:1
Perimeter of the park = 2(l + b ) = 320
let the each ratio be 3:1
According to the problem,
2(3x + x ) = 320
4x = 320/2
4x = 160
x = 160/4
x = 40
Breadth = x = 40
length = 3x = 120
Area of the park :
= l × b
= 120 × 40
= 4800sq m
When the path goes inside the park then it Subtracts 4 metres from the length and breadth.
breadth = 40 - 4 = 36
length = 120 - 4 = 116
Area of this :
= 116 × 36
= 4176 sq m
Area of the path : Area of total park - Area of inner park
= 4800 - 4176
= 624 sq m
Therefore, the area of the path is 624 sq m.
The cost of paving for one metre = ₹ 3
Then the cost of paving for 624 sq m :
= 624 × 3
= 1872
Therefore, the cost of paving = ₹ 1872