The length and breadth of a rectangle are 10cm and 8cm respectively . Find its perimeter if the length and breadth are doubled ?
Answers
Answer:
323cm^2
Step-by-step explanation:
Given
Length of rectangle l=10 cm and
Breadth of rectangle b=8 cm
Perimeter =2 (Length + Breadth)
=2(10+8) cm
=2×18
=36 cm
If each side of the rectangle is increased by x cm , then ,
Perimeter =2(10+x+8+x)
=2(18+2x)
=(36+4x) cm
According to the given condition,
36+4x=2(36)
36+4x=72
4x=72−36
4x=36
x=
4
36
We get ,
x=9
Hence ,
Length of new rectangle =1+x=10+9=19 cm and
Breadth of new rectangle =b+x=8+9=17 cm
Area = Length × Breadth =19×17cm
2
=323cm^2
Answer:
72 cm
Step-by-step explanation:
Given,
Length of a rectangle = 10 cm
Breadth of a rectangle = 8 cm
doubled length = 10 cm x 2 = 20 cm
doubled breadth = 8 cm x 2 = 16 cm
Perimeter of rectangle = 2 x ( l + b )
= 2 x ( 20 cm + 16 cm )
= 2 x 36 cm
= 72 cm
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