Question

The length and breadth of a rectangle are 12.5 cm and 9.5 cm respectively. Find the area of the rectangle.​

Answer 1

Solution:

Length of a rectangle = 12.5cm

Breadth of a rectangle = 9.5cm

Area of rectangle = Length × Breadth

Area of rectangle = 12.5 × 9.5

Area of rectangle = 118.75cm²

$\tt\underline{Additional\space Information}$

Perimeter of a square = 4 x side

Perimeter of a rectangle = 2(l + b)

Area of a square = (side)²

Area of a rectangle = l × b

Area of a parallelogram = b × h

Area of a triangle = 1/2 × b × h

Area of circle = πr².

Answer 2

Given Information :-

The length and breadth of a rectangle are 12.5 cm and 9.5 cm respectively. Find the area of the rectangle.

• Length of Rectangle = 12.5 cm
• Breadth of Rectangle = 9.5 cm
• Area of Rectangle = ?

Formula used :-

★ Area of rectangle = L × B

Where,

• L = Length of rectangle
• B = Breadth of rectangle

Putting all values :-

➦ Area of rectangle = 12.5 × 9.5

➦ Area of rectangle = 118.75 cm²

Henceforth, The Area of Rectangle is 118.75 cm²

LEARN MORE :-

$\begin{gathered}\begin{gathered}\boxed{\begin {minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}\end{gathered}\end{gathered}$