Question

The length and breadth of a rectangle are 12 cm and 9 cm respectively.Find the side of the square with its perimeter equal to that of the rectangle. ​

Answer 1

Step-by-step explanation:

Length=12cm

Breadth=9cm

Area of rectangle=length×breadth=12×9 cm2=108cm2

∴ Area of triangle=31 of Area of rectangle =31×108 cm2=36cm2

Base of the triangle =9cm

Area of triangle=21×base×height

⇒36=21×9×height

⇒height=8 cm

Answer 2

Step-by-step explanation:

Given :-

The length and breadth of a rectangle are 12 cm and 9 cm respectively.

To find :-

Find the side of the square with its perimeter equal to that of the rectangle?

Solution :-

Given that

Length of the rectangle (l) = 12 cm

Breadth of the rectangle (b) = 9 cm

We know that

Perimeter of a rectangle = 2(l+b) units

Perimeter of the given rectangle

=> P = 2(12+9) cm

=> P = 2(21) cm

=> P = 42 cm

Let the side of a square be a cm

Perimeter of a square = 4a units

Given that

Perimeter of square = Perimeter of a rectangle

=> 4a = 42

=> a = 42/4

=> a = 21/2

=> a = 10.5

Therefore, side of the square = 10.5 cm

Answer:-

The side of the square is. 10.5 cm

Used formulae:-

→Perimeter of a rectangle = 2(l+b) units

• l = length of the rectangle
• b = breadth of the rectangle

→Perimeter of a square = 4a units

• a = Side of the square