Question

The length and breadth of a rectangle are 25 cm
and 15 cm. Find the ratio of
(a) its length to its breadth.
(b) its length to its perimeter
(c) its breadth to its perimeter.
186
Pls solve​

Answer 1

$\sf \bf \huge {\boxed {\mathbb {QUESTION}}}$

$\tt The\: length\: and\: breadth\: of\: a\: rectangle\\\tt are\: 25\: cm\: and\: 15 \:cm\:. Find\: the \:ratio\: of$

$\tt (a) its\: length\: to\: its \:breadth\:.$

$\tt (b) its\: length\: to \:its \:perimeter\:.$

$\tt (c) its \:breadth\: to\: its\: perimeter\:.$

$\sf \bf \huge {\boxed {\mathbb {ANSWER}}}$

$\sf \bf {\boxed {\mathbb {GIVEN}}}$

• $\sf \bf Length\:of\:rectangle(l) =25\:cm$
• $\sf \bf Breadth\:of\:rectangle(b) =15\:cm$

$\sf \bf {\boxed {\mathbb {TO\:FIND}}}$

• $\sf \bf Perimeter\:of\:rectangle(P)$
• $\sf \bf (a) its\: length\: to\: its \:breadth\:.$
• $\sf \bf (b) its\: length\: to \:its \:perimeter\:.$
• $\sf \bf (c) its \:breadth\: to\: its\: perimeter\:.$

$\sf \bf {\boxed {\mathbb {SOLUTION}}}$

$\sf \bf{\underbrace{\overbrace {Perimeter\:of\:rectangle}}}$

${\boxed {\boxed{\boxed {\color{blue} {P=2(l+b)}}}}}$

• $\sf \bf P= perimeter$
• $\sf \bf l= length$
• $\sf \bf b= breadth$

$\tt \underline {Substitute\: the\: values}$

$\sf \bf \implies P=2(25+15)$

$\sf \bf \implies P=2(40)$

$\implies{\boxed{\boxed {\color{red} {P=80\:cm}}}}$

------------------------------------------------------------

${\boxed {\color{purple} {\sf \bf Length\:of\:rectangle=25\:cm}}}$

${\boxed {\color{purple} {\sf \bf Breadth\:of\:rectangle=15\:cm}}}$

${\boxed {\color{purple} {\sf \bf Perimeter\:of\:rectangle=80\:cm}}}$

------------------------------------------------------------

${\underbrace {\overbrace {\color{orange} {\sf \bf (a) its\: length\: to\: its \:breadth\:.}}}}$

$\sf \bf \implies 25:15$

${\boxed {\boxed {\color {green} {\sf \bf 5:3}}}}$

------------------------------------------------------------

${\underbrace {\overbrace {\color{orange} {\sf \bf (b) its\: length\: to\: its \:perimeter\:.}}}}$

$\sf \bf \implies 25:80$

${\boxed {\boxed {\color {green} {\sf \bf 5:16}}}}$

------------------------------------------------------------

${\underbrace {\overbrace {\color{orange} {\sf \bf (c) its\: breadth\: to\: its \:perimeter\:.}}}}$

$\sf \bf \implies 15:80$

${\boxed {\boxed {\color {green} {\sf \bf 3:16}}}}$

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$\sf \bf \huge {\boxed {\mathbb {HOPE \:IT \:HELPS \:YOU}}}$

__________________________________________

$\sf \bf \huge {\boxed {\mathbb {EXTRA\:INFORMATION}}}$

$\tt {\underbrace {\overbrace {Formulas}}}$

$\sf \bf Perimeter\:of\:rectangle = 2(l+b)$

$\sf \bf Perimeter\:of\:square = 4a$

$\sf \bf Perimeter\:of\:triangle = a+b+c$

$\sf \bf Perimeter\:of\:circle = 2 \pi r$

${\mathbb{\colorbox {orange} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {lime} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {aqua} {@suraj5070}}}}}}}}}}}}}}}$

Answer 2

a. 5:3

b. 5:16

c. 3:16

hope it helpss...!!!