Question

The length and breadth of a rectangle are 4.8 cm and 3.2 cm. The area of this rectangle is​

Answer 1

Answer:

Length of rectangle =4.8 cm

Breadth of rectangle = 3.2 cm

Area = Length * Breadth

        = ( 4.8*3.2 ) cm square

        = 15.36 cm square

Step-by-step explanation:

Answer 2

Answer:

• 15.36 cm² is the required area of rectangle .

Step-by-step explanation:

According to the Question

It is given that,

• Length ,l = 4.8cm
• Breadth ,b = 3.2 cm

we have to calculate the area of rectangle .

As we know that area of rectangle is calculated by

Area of Rectangle = Length × Breadth

on substituting the value we get

→ Area of Rectangle = 4.8 × 3.2

→ Area of Rectangle = 15.36 cm²

• Hence, the area of rectangle is 15.36 cm².

Additional Information !!

$\begin{gathered}\boxed{\begin {array}{cc}\\ \quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}$