Question

The length and breadth of a rectangle are 48 cm and 21 cm respectively. The side of a square is two-thirds the length of the rectangle. The sum of their areas( in square cm ) is....................?​

Answer 1

$given \: length \: and \: breadth \: of \: a \: rectangle \: = 48cm \: and \: 21cm \\ \\ area \: of \: rectangle \: = length \times breath = 48 \times 21 = 1008cm {}^{2} \\ \\ given \: side \: of \: square \: = \frac{2 \times length \: of \: rectangle}{3} = 32cm \\ \\ area \: of \: square = (s) {}^{2} = (32) {}^{2} = 1024cm {}^{2} \\ \\ sum \: of \: their \: areas \: = 1008 + 1024 = 2032cm {}^{2}$

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Answer 2

please refer to the attachment