Question

The length and breadth of a rectangle are 64 /5 m and 19/2m respectively. find its perimeter?​

Answer 1

Answer:

Perimeter =

$2( \frac{64}{5} + \frac{19}{2} ) \\ 2( \frac{128 + 95}{10} ) \\ 2 \times \frac{223}{10} = \frac{223}{5} = 44 \frac{3}{5}$

Hope it helps....

Answer 2

$\huge\mathbb\blue{♡Answer♡}$

Step-by-step explanation:

Given

length=64/5

breadth=19/2

perimeter of rectangle=2(l+b)

$\huge{2 ( \frac{64}{5} + \frac{19}{2}}) \\ lcm of denominator = 10 \\ \\ 2(\frac{128+ 95}{10}) \\ \\ 2(\frac{223}{10})\\ \frac{ 223}{5} or \\ 2(22.3)\\44.6cm$