The length and breadth of a rectangle are (7x-y) Units and (x+5y) units respectively. The perimeter of this rectangle is equal to the perimeter of a square. Find how much is the area of the rectangle less than that of the square
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Answer:
2(l×b)
2(2x+5y+x-8y)
4x+10y+2x-8y
6x+2y
so, the perimeter is 6x+2y
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