Question

the length and breadth of a rectangle are 9 cm and 4cm respectively. The perimeter of a square is 10cm greater than that of the rectangle. What is the area of the square

Answer 1

Let l,b be the length and breadth of the rectangle and s be the side of the square

Given that

⇒2(l+b)=4s

⇒2(10+8)=4s

⇒2×18=4s

⇒4s=36

⇒s=9

So, Area of square =s

2

⇒ Area of square =9

2

⇒ Area of square =81 sq. cm

Answer 2

Answer:

81 sq.cm

Step-by-step explanation:

Length of Rectangle= 9cm

Breadth of Rectangle= 4cm

Perimeter of Rectangle= 2(l+b)

                                      = 2(9cm+4cm)

                                      = 2(13cm)

                                      = 2*13cm

                                      =26 cm

Perimeter of Square= 10cm+Perimeter of Rectangle

= 10cm+26cm

=36cm

Side of Square= Perimeter/4

= 36cm/4

= 9cm

Area of a Square= s*s

= 9cm*9cm

=81 sq.cm

Therefore,  the Area of the Square= 81sq.cm