Question

the length and breadth of a rectangle are a + 5 units and 7a -
b units respectively the perimeter of the rectangle is equal to perimeter of a square find how much is the area of the rectangle less than that of the square

Answer 1

perimeter of rectangle=2(l+b)
2(a+5b+7a-b)
2a+10b+14a-2b
​p=16a-8b=the area of square
therefore side of square 16a-8b divided by 4
4a+2b=side of square
area of square =4a+2bX4a+2b
(a+b)2=a2+2ab+b2

so area =16a2​+16ab+4b2    (1)

area of rctangle =lXb=(a+5b)X(7a-b)
=7a2-ab+35ab-5b2       (2)


(1)-(2)=9a2-18ab+9b2  this much is the area of rectangle less than that of square
0


9a+b

0
 

Answer 2

Answer:

perimeter of rectangle=2(l+b)

2(a+5b+7a-b)

2a10b+14a-2b

​p=16a-8b=the area of square

therefore side of square 16a-8b divided by 4

4a+2b=side of square

area of square =4a+2bX4a+2b

(a+b)2=a2+2ab+b2

so area =16a2​+16ab+4b2    (1)

area of rctangle =lXb=(a+5b)X(7a-b)

=7a2-ab+35ab-5b2       (2)

(1)-(2)=9a2-18ab+9b2  this much is the area of rectangle less than that of square