Question

The length and breadth of a rectangle are (a+5b) units and (7a-b) units respectively. The perimeter of this rectangle is equal to the perimeter of a square. Find how much is the area of the rectangle less than that of the square?​

Answer 1

Answer:

First we will take te perimeter 2(a+b) then we will

find the value of b which is 15a/8 then we have the value of b then take the perimeter by putting b value then a will be in no. then the sum will be solved