Question

the length and breadth of a rectangle are a plus 5 units and 7 minus b units respectively the perimeter of the rectangle is equal to the perimeter of a square. find how much is the area of the rectangle less than that of the square? please help me guys ​

Answer 1

Answer:

shrajalchoudhary

Perimeter of rectangle=2(l+b)

2(a+5b+7a-b)

2a+10b+14a-2b

p=16a-8b=the area of square

therefore side of square 16a-8b divided by 4

4a+2b=side of square

area of square =4a+2bX4a+2b

(a+b)2=a2+2ab+b2

so area =16a2+16ab+4b2    (1)

area of rctangle =lXb=(a+5b)X(7a-b)

=7a2-ab+35ab-5b2       (2)

(1)-(2)=9a2-18ab+9b2  this much is the area of rectangle less than that of square

0

9a+b

0

Answer 2

Step-by-step explanation:

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