Question

The length and breadth of a rectangle are consecutive odd integers and the perimeter is 168 cm. Find the length and breadth of the rectangle​

Answer 1

Step-by-step explanation:

The perimeter of a rectangle = 168cm

Let length(l) = x=x and breadth(b) =x+2=x+2

To find, the length and width of the triangle = ?

We know that,

The perimeter of rectangle =2(Length + Breadth)

⇒2[x+(x+2)]=1682[x+(x+2)]=168

⇒x+(x+2)=\dfrac{168}{2} =84x+(x+2)=

2

168

=84

⇒2x+2=842x+2=84

⇒2x = 84-2 =822x=84−2=82

⇒x=\dfrac{82}{2} =41x=

2

82

=41

∴ x + 2 = 41 + 2 = 43 cm

Hence, the length and width of the rectangle are 41 cm and 43 cm.