The length and breadth of a rectangle are in ratio 9:5 .If the area of the field is 14580 square metre find the cost of surrounding the field with a fence at the rate of Rs3.25 per metre
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Answered by
22
Let the length and breadth be 9x and 5x
So,
9X x 5X = 14580
45x square = 14580
X square = 14580/45
X square = 324
X = 324 under root
X = 18
So,length =9 x 18 = 162
And, breadth =5 x 18 = 90
Now, its perimeter = 2( L + B )
=2(162 + 90)
=2 x 252
=504
Now, cost of fencing the field
=504 x 3.25
=1938.00
So,cost of fencing the field = rs 1938
Hope it helps...!!! <><>
So,
9X x 5X = 14580
45x square = 14580
X square = 14580/45
X square = 324
X = 324 under root
X = 18
So,length =9 x 18 = 162
And, breadth =5 x 18 = 90
Now, its perimeter = 2( L + B )
=2(162 + 90)
=2 x 252
=504
Now, cost of fencing the field
=504 x 3.25
=1938.00
So,cost of fencing the field = rs 1938
Hope it helps...!!! <><>
Answered by
1
Answer:
Page 1
First of all,you have to take the ratio in x
Then, 9x+5x=14580
solve the sum ,ur ans. will be 18
.Length= 9×18=162
.Breadth=5×18=90
Page 2
Perimeter=2(L+B)
=2(162+90)
=504
At last,,,,,,
Cost of fencing the field
=504×3.25
=1938 (ans.)
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