Question

The length and breadth of a rectangle are two consecutive even positive integers, if the perimeter is 44 cm, find the length and breadth of the rectangle.​

Answer 1

$\large{\underline{\underline{ \bf{⎆Question:-}}}}$

• The length and breadth of a rectangle are two consecutive even positive integers, if the perimeter is 44 cm, find the length and breadth of the rectangle.

$\large{\underline{\underline{ \bf{➫Solutìon:-}}}}$

$\small\underline{\overline{\mid{\bold{\red{☂Lèt-}}\mid}}}$

• Length (L) : x + 2
• Breadth (B) : x + 4

$\underline{ \boxed{ \sf{Perimeter = 2(L + B) }}}$

$\small\underline{\overline{\mid{\bold{\red{☂ Here-}}\mid}}}$

$\longmapsto$ Perimeter = 2[ x + 2 + x + 4 ]

$\longmapsto$ Perimeter = 2 × ( 2x + 6 )

$\longmapsto$ Perimeter = 4x + 12

Given Perimeter : 44cm

$\large{\underline{\underline{ \bf{➥Therefore:-}}}} [tex]</p><p></p><p></p><p>[tex] \longmapsto$ 44 cm = 4x + 12

$\longmapsto$ 44 - 12 = 4x

$\longmapsto$ 4x = 32

$\longmapsto$ x = 8

$\small{\underline{\underline{ \bf{⇝So:-}}}}$

↬ Length = 8 + 2 = 10 cm

↬ Breadth = 8 + 4 = 12 cm