Question

the length and breadth of a rectangle are x+4 cm and x-4 cm respectively and it's perimeter is 52 cm then what is it's area​

Answer 1

Step-by-step explanation:

I'm sending in photo plz check in it

and give me thanks and this to brain list

plz follow me..... .............

Answer 2

Given :-

Length of the rectangle = x + 4

Breadth of the rectangle = x - 4

Perimeter of the rectangle = 52 cm

To Find :-

The length of the rectangle.

Breadth of the rectangle.

The area of the rectangle.

Analysis :-

According to the question, make and equation substituting the values in the formula.

Find the values of x and apply them to get the length and breadth.

Substitute the value of length and breadth in the formula of area of a rectangle and find it's area.

Solution :-

We know that,

• l = Length
• b = Breadth
• p = Perimeter
• a = Area

Given that,

Length (l) = x + 4

Breadth (b) = x - 4

Perimeter (p) = 52 cm

By the formula,

$\underline{\boxed{\sf Perimeter \ of \ a \ rectangle=2(Length+Breadth)}}$

Substituting their values,

Perimeter of the rectangle = $\sf 2(x+4+x-4)=52$

$\sf =2(2x)=52$

$=\sf 4x=52$

$=\sf x=\dfrac{52}{4}$

$=\sf x=13$

Length = $\sf x+4$

$\longrightarrow \sf 13+4=17 \ cm$

Breadth = $\sf x-4$

$\longrightarrow \sf 13-4=9 \ cm$

Therefore, the length and breadth is 17 cm and 9 cm respectively.

Finding the area,

$\underline{\boxed{\sf Area \ of \ a \ rectangle=Length \times Breadth}}$

Substituting their values,

Area of the rectangle = $\sf 17 \times 9$

$\sf \longrightarrow 153 \ cm^{2}$

Therefore, the area of the rectangle is 153 cm²