Question

the length and breadth of a rectangle field are in the ratio 4:3 it's area is 6912m² find the last af fencing the field at rupees 2.50 per meters​

Answer 1

Answer:

Rs 840

Step-by-step explanation:

Let length and breadth be 4x and 3x.

Area of rectangle = l×b

⇒ 6912m² = 4x×3x

⇒ 6912 = 12x²

⇒ 6912/12 = x²

⇒ √576 = x

⇒ 24 = x

So, length = 24*4 = 96m

     breadth = 24*3 = 72m

Now, Perimeter of rectangle = 2(l+b) = 2(96+72) = 2*168

= 336m

∴ cost of fencing at Rs 2.50 per m = 336×2.50

= Rs 840

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