Question

the length and breadth of a rectangle hall is 12.5 m and 9m respectively find (1) area of the hall (2) perimeter of the hall?​

Answer 1

Step-by-step explanation:

Area = L × B

= 12.5 × 8

= 100 m²

Perimeter = 2(L + B)

= 2(12.5 + 8)

= 2(20.5)

= 41 m

hope it helps

Answer 2

Answer:

(1) Therefore the area of the rectangle hall is $112.5\;m^{2} .$

(2) Hence the perimeter of the rectangle hall is 43 m.

Step-by-step explanation:

As per the data provided in the given question.

The given data is as follows,

The length of a rectangle (l) is 12.5 m and breadth of a rectangle is 9 m.

The breadth of a rectangle represent the width of rectangle (w).

(1) We have to find the area of the rectangle hall(A).

Here we will be using the formula of  area of the rectangle.

$A=l\times w$

Now we will substitute the given value in above formula.

$A=12.5\times9$

We will multiply the above values,

$A=112.5\;m^{2}$

Therefore the area of the rectangle hall is $112.5\;m^{2} .$

(2) Now we have to find perimeter of the rectangle hall (P).

Here we will be using the formula of perimeter of the rectangle hall.

$P=2(l+w)$

Now we will substitute the given value in above formula.

$P=2(12.5+9)$

At first we will add the values inside the brackets

[tex]P=2(21.5)\\ P=2\times21.5[/tex]

Now we will multiply the above values,

Further, we get

$P=43\;m$

Hence the perimeter of the rectangle hall is 43 m.