Question

the length and breadth of. a rectangle is 16 m by 9 . Find the cost of surrounding the field with a fence at the rate ₹ 3.25 per metre ??​

Answer 1

Answer:

perimeter of the rectangle = 2(length + breadth)

= 2(16+9)

=2 × 25

= 50 m

cost of surrounding the field with fencing at the rate of 3.25 rupees/m = perimeter × cost

= 50 × 3.25

= 162.5 Rupees

Step-by-step explanation:

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Answer 2

Correct Question-:

• The length and breadth of a rectangle is 16 m and 9m . Find the cost of surrounding the field with a fence at the rate ₹ 3.25 per metre ?

AnswEr-:

• $\underline{\boxed{\star{\sf{\blue{ The\:cost\:of\:fencing\;of\:the\:Rectangular \:field \:is  \: =Rs.162.5 }}}}}$

Explanation-:

• $\frak{Given \:\: -:} \begin{cases} \sf{The\:Length \:of\:Rectangle\:\:is\:= \frak{16m}} & \\\\ \sf{Breadth \:of\:Rectangle \:is \:=\:\frak{9m}}& \\\\ \sf{The\:cost\:of\:surrounding \: the\:field \: with\:fence at \:the \:rate\:of\:₹ 3.25\: per\: metre}\end{cases}$

• $\frak{To\:Find \:\: -:} \begin{cases} \sf{The\:cost\:of\:surrounding \: the\:field \: with\:fence at \:the \:rate\:of\:₹ 3.25\: per\: metre .}\end{cases}$

$\dag{\underline {\sf{Solution \:of\:Question \:-:\:}}}$

• $\underbrace{\sf{\large{Understanding \:Concept \:-:}}}$

• We have to surround the boundary of the Rectangular field using fence .

• As, we know that ,

• Boundary of Rectangular field = Perimeter of Rectangular Field

Now,

• $\underline{\boxed{\star{\sf{\blue{ Perimeter_{(Rectangle)}  \: = \: 2 \times ( Length + Breadth)}}}}}$

• $\frak{Here \:\: -:} \begin{cases} \sf{The\:Length \:of\:Rectangle\:\:is\:= \frak{16m}} & \\\\ \sf{Breadth \:of\:Rectangle \:is \:=\:\frak{9m}}\end{cases}$

Now , By putting known Values in Formula,

• $\longrightarrow {\sf{ 2 ( 16 + 9)}}$

• $\longrightarrow {\sf{ 2 ( 25)}}$

• $\longrightarrow {\sf{ 50 m}}$

$\dag{\underline {\sf{ Therefore :-:\:}}}$

• 1$\underline{\boxed{\star{\sf{\blue{ Perimeter_{(Rectangular\:Field)}  \: =50 m }}}}}$

$\dag{\underline {\sf{ Now :-:\:}}}$

• $\underline{\boxed{\star{\sf{\blue{ The\:cost\:of\:Fencing\:=}}}}}\\\\\underline{\boxed{\star{\sf{\blue{ The\:cost\:of\:fencing\:at\:the\:rate\:of\:per\:metre \times The \:Perimeter\:of\:Rectangular\:Field. }}}}}$

• $\dag{\underline {\sf{ Here :-:\:}}}$

• $\longrightarrow {\sf{ Perimeter_{(Rectangle)} = 50m}}$

• $\sf{The\:cost\:of\:surrounding \: the\:field \: with\:fence at \:the \:rate\:of\:₹ 3.25\: per\: metre}$

• $\dag{\underline {\sf{ Then :-:\:}}}$

• $\longrightarrow {\sf{ 50 \times 3.25}}$

• $\longrightarrow {\sf{ Rs.162.5 }}$

$\dag{\underline {\sf{ Hence :-:\:}}}$

• $\underline{\boxed{\star{\sf{\blue{ The\:cost\:of\:fencing\;of\:the\:Rectangular \:field \:is  \: =Rs.162.5 }}}}}$

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