Question

the length and breadth of a rectangle is 48 dm and 3.6 m. find the area and perimeter in cm.

Length:
1 dm =10 cm
48 dm = 10×48 = 480 cm

Breadth:
1 m= 100cm
3.6m= 100×3.6 = 360cm

area of a rectangle=l×b
480×360 = 172800cm^

perimeter of a rectangle
2(L+B)
2(480+360)
1680cm

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Answer 1

Length:

1 dm =10 cm

48 dm = 10×48 = 480 cm

Breadth:

1 m= 100cm

3.6m= 100×3.6 = 360cm

area of a rectangle=l×b

480×360 = 172800cm^

perimeter of a rectangle

2(L+B)

2(480+360)

1680cm

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Answer 2

Answer:

Find the perimeter of a rectangle whose length and width are 25 m and 15 m respectively.

Solution :

Length = l = 25 m and Width = w = 15 m

∴ P = 2 ( l + w )

⇒ = 2 ( 25 + 15 )

⇒ = 2 x 40

⇒ = 80 m

Perimeter = 80 m

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2)How many rectangles can be drawn with 36 cm as the perimeter, given that the sides are positive integers in cm ?

Solution :

Perimeter = 36

⇒ 2 ( l + w ) = 36

⇒ l + w = 18

Since length and width are positive integers in centimeters. Therefore, possible dimensions are :

( 1, 17 )cm , ( 2, 16 ) cm , ( 3, 15 ) cm, (4 , 14) cm, ( 5,13) cm, ( 6, 12) cm , ( 7, 11) cm, ( 8, 10 ) cm, ( 9, 9) cm.

Hence, there are 9 rectangles.

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4) The length of a rectangular field is twice its width. A man jogged around it 5 times and covered a distance of 3 km. What is the length of the field?

Solution :

In completing one round of the field distance covered is equal to the perimeter of the field.

∴ Distance covered in 5 rounds = 5 x Perimeter

= 5 x 2 ( l + w )

= 10 x ( l + w)

= 10 x ( 2w + w ) [ length = l = 2w ]

= 10 x 3w

= 30 w

But, the total distance covered is given = 3 km = 3000 m.

∴ 30 x w = 3000

⇒ w = 3000 / 30

⇒ w = 100 m

⇒ Length = 2 w = 2 x 100 = 200 m.