the length and breadth of a rectangle is 80cm and 40cm respectively.four square of side 5cm each are removed from its four corners. find the remaining area
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1)given
length of rectangle =80
breadth of rectangle =40
perimeter =2×l+b
=2×80+40
=2×120
=240
2)given
side of square =5
perimeter =s×s
=5×5
=25
perimeter of rectangle-perimeter of triangle =area
240-25=area
215=area
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