the length and breadth of a rectangle piece of land are in ratio 5:2 if the total cost of fencing it at Rs 12.5 per metre is Rs 25000 find its length and breadth
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The length and breadth have a ratio 5:2.
Let the common multiple be x.
So, length = 5x m and breadth = 2x m.
The perimeter of the rectangle be
2 × ( length + breadth)
= 2 × (5x + 2x) m
= 14x m.
Hence,
14x = 25000/12.5
or, 14x = 2000
or, x = 1000/7
So length is 5000/7 m and breadth is 2000/7 m.
The length and breadth have a ratio 5:2.
Let the common multiple be x.
So, length = 5x m and breadth = 2x m.
The perimeter of the rectangle be
2 × ( length + breadth)
= 2 × (5x + 2x) m
= 14x m.
Hence,
14x = 25000/12.5
or, 14x = 2000
or, x = 1000/7
So length is 5000/7 m and breadth is 2000/7 m.
Answered by
1
Perimeter of rectangular piece of land=
Total cost of fencing /rate of fencing
=25000/12.5
=2000m^2
Let length be 5x, breadth be 2x
Perimeter of plot=2(l+b)
2000=2(5x+2x)
2000/2=7x
1000/7=x
Length =5x=5×1000/7=5000/7m
Breadth =2x=2×1000/7=2000/7m
Total cost of fencing /rate of fencing
=25000/12.5
=2000m^2
Let length be 5x, breadth be 2x
Perimeter of plot=2(l+b)
2000=2(5x+2x)
2000/2=7x
1000/7=x
Length =5x=5×1000/7=5000/7m
Breadth =2x=2×1000/7=2000/7m
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