Physics, asked by meenakumari70730, 7 months ago


The length and breadth of a rectangular field are 22:4 cm and
15.8 cm respectively and have been measured to an
accuracy of O2 cm. Find the percentage error in the area of
the field.

Answers

Answered by siddhivinayak80
1

Answer:

It is given in the problem that the length and breath of a field are 22.4 cm and 15.8 cm respectively and have been measured to an accuracy of 0.2 cm. Put L= 22.4 cm, B= 15.8 cm and and . Therefore, the error in the area of the field is 2.09%.

46

Answered by patidaruttkarsh
1

Answer: The correct answer is 2.09%.

Explanation:

The expression for the area of the rectangle.

A=LB

Here, L is the length and breadth of the rectangle.

Calculate the error in the area of the field.

\frac{\delta A}{A}\times 100=\frac{\Delta L}{L}\times 100+\frac{\Delta B}{B}\times 100

A

δA

×100=

L

ΔL

×100+

B

ΔB

×100

It is given in the problem that the length and breath of a field are 22.4 cm and 15.8 cm respectively and have been measured to an accuracy of 0.2 cm.

Put L= 22.4 cm, B= 15.8 cm and \Delta L= 0.2 cmΔL=0.2cm and \Delta B= 0.2 cmΔB=0.2cm .

\frac{\delta A}{A}\times 100=\frac{ 0.2}{22.4}\times 100+\frac{0.2}{15.8}\times 100

A

δA

×100=

22.4

0.2

×100+

15.8

0.2

×100

\frac{\delta A}{A}\times 100= 2.09%

A

δA

×100=2.09

Therefore, the error in the area of the field is 2.09%.

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