Question

the length and breadth of a rectangular field are respectively 80 m and 60m. two matually perpendicular passage, one is parallel to its length and having width 5 m while the other is parallel to breadth and having width 3 m are left in the central part. what is the total cost of passage at the rate of ₹ 20 per sq. m? also find the area of remaining part of the field​

Answer 1

Answer:

firstly area of rectangular field then passage add them and neatly multiply passage area with 20

Answer 2

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The length and breadth of a rectangular field are respectively 80m and 60m. Two mutually perpendicular passage, one parallel to its length and having width 5m while the other its length and having width 3m are left in the central part. What is the total cost of passage at the rate of Rs 20 per.sq.m? Also find the area of remaining part of the field.

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Area of Rectangular field = Length ×

Breadth

= 80m × 60m

= 4800m²

Area of road EFGH = Length × Breadth

= 60m × 3m

= 180m²

Area of Road IJKL = Length × Breadth

= 80m × 5m

= 400m²

Area of rectangle common in two roads = 5m × 3m = 15m²

Area covered by Roads = 180m²+400m²-15m²

= 580m²- 15m²

= 565m²

Cost of 1m² = Rs20

Cost of 565m²= Rs20 × 565

= Rs11,300

Remaining Part of Rectangular field = 4800 – (180+400-15)

= 4800 – 565

= 4235m²

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