Question

The length and breadth of a rectangular field are in ratio 3:2. if the area of the field is 3456m sq. Find the cost of fencing the field at Rs. 2.50 per meter.
Please give solution....
Answer = "Rs. 600."
Tell me how it solve​

Answer 1

this is the answer of your question

Answer 2

Answer :-

The Amount required to Fence the Rectangular ground is Rs.600

Explanation :-

Given :

Ratio of sides = 3:2

Area of the Rectangle = 3456 sq.m

Rate of Fencing = Rs. 2.50 per meter.

To find :

The total money required to Fence the ground

Solution :

Consider the Length as 3x

Consider the Breadth as 2x

$\star$ Area of Rectangle =

$\boxed{\sf{Length \times Breadth}}$

$\sf{\implies}3x \times 2x = 3456$

$\sf{\implies} {6x}^{2} = 3456$

$\sf{\implies} {x}^{2} = \dfrac{3456}{6}$

$\sf{\implies} {x}^{2} = 576$

$\sf{\implies}x = \sqrt{576}$

$\begin{array}{r|l} 2 & 576 \\\cline{1-2} 2 & 288 \\\cline{1-2} 2 & 144 \\ \cline{1-2} 2 & 72 \\\cline{1-2} 2 & 36 \\\cline{1-2} 2 & 18 \\\cline{1-2}3 & 9 \\\cline{1-2} 3 & 3 \\\cline{1-2} & 1 \end{array}$

Square root = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3

→ 2 × 2 × 2 × 3

→ 24

$\sf{\implies}x = 24$

Value of 3x

$\sf{\implies}3 \times x$

$\sf{\implies}3 \times 24$

$\sf{\implies}72$

$\boxed{\sf{\red{Length = 72 \: m}}}$

Value of 2x

$\sf{\implies}2 \times x$

$\sf{\implies}2 \times 24$

$\sf{\implies}48$

$\boxed{\sf{\red{Breadth = 48 \: m}}}$

To get the Fencing length we need to find the Perimeter of the Rectangle.

$\star$ Perimeter of Rectangle :

$\boxed{\sf{2(length + breadth)}}$

$\sf{\implies}2(72 + 48)$

$\sf{\implies}144 + 96$

$\sf{\implies}240$

Perimeter = 240 m

$\star$ Cost of Fencing =

$\sf{\implies}240 \times 2.5$

$\sf{\implies}600$

$\boxed{\sf{\red{Cost = Rs.600}}}$

$\therefore$ The Amount required is Rs.600