the length and breadth of a rectangular field are in the ratio 5:4 and its area is 3380m square. find the cost of fencing it at the rate of ₹75per m.
Answers
Answered by
71
let length , breadth be in ratio 5x ,4x (m) resp.
so Area =length×breadth
3380 =5x × 4x
20x^2=3380
x^2=169
x=13
so length=5x=65m
breadth=4x=52m
perimeter=2(l+b)=2(65+52)=2× 117=234m
so the cost of fencing=75×234=Rs.17550
so Area =length×breadth
3380 =5x × 4x
20x^2=3380
x^2=169
x=13
so length=5x=65m
breadth=4x=52m
perimeter=2(l+b)=2(65+52)=2× 117=234m
so the cost of fencing=75×234=Rs.17550
Answered by
32
5x×4x=3380
20x^2=3380
x^2=169
x=13
so its length=65m
and its breadth=52m
now,perimetre=2(l+b)
=2(65+52)
=2×117
=234m
now,the cost of fencing=234×75
=17550₹
20x^2=3380
x^2=169
x=13
so its length=65m
and its breadth=52m
now,perimetre=2(l+b)
=2(65+52)
=2×117
=234m
now,the cost of fencing=234×75
=17550₹
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