The length and breadth of a rectangular field are in the ratio 3 : 2. If the perimeter of the field is 250 m,
find the cost of reaping the field at 15 per 50 m².
WITH EXPLAINTION
Answers
Answer:
Okay, let's draw the figure.
We first need to find the area of the field.
The ratio of the field is 3:2
Let Lenght (l)=2x, Breadth (b)=3x.
Then, Perimeter=2(l+b)
[Substitute the values of perimeter, length, and breadth]
250=2(2x+3x)
250÷2=5x
125=5x
x=125÷5
x=25.
Now, l⇒2x⇒2×25⇒50m.
b=3x⇒3×25=75m.
Area=l×b=50×75
Area=3750m²
Then we know that cost of reaping the field is 15₹ per 50m².
Then, we need to find the cost of reaping the field at 3750m².
The required cost: (3750÷50)×15=1125₹
HOPE THIS HELPS :D
Answer:
the next part of the question is:
area of the field= l×b
= 75m×50m
=3750m²
Cost of reaping 50m² of the field = 15 Rupees
Cost of reaping 1m² of the field = 15/50
=3/10= 0.3 Rupees
cost of reaping the whole field = 0.3×3750
=1125 Rupees
PLEASE MARK ME AS THE BRAINLIEST!!! AND THIE QUESTION SHOULD BE MINIMUM OF 10 POINTS!