Math, asked by sai9586, 6 months ago


The length and breadth of a rectangular field are in the ratio 3 : 2. If the perimeter of the field is 250 m,
find the cost of reaping the field at 15 per 50 m².

WITH EXPLAINTION​

Answers

Answered by SujalSirimilla
18

Answer:

Okay, let's draw the figure.

We first need to find the area of the field.

The ratio of the field is 3:2

Let Lenght (l)=2x, Breadth (b)=3x.

Then, Perimeter=2(l+b)

[Substitute the values of perimeter, length, and breadth]

250=2(2x+3x)

250÷2=5x

125=5x

x=125÷5

x=25.

Now, l⇒2x⇒2×25⇒50m.

b=3x⇒3×25=75m.

Area=l×b=50×75

Area=3750m²

Then we know that cost of reaping the field is 15₹ per 50m².

Then, we need to find the cost of reaping the field at 3750m².

The required cost: (3750÷50)×15=1125₹

HOPE THIS HELPS :D

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Answered by RaghavMakkar
13

Answer:

the next part of the question is:

area of the field= l×b

= 75m×50m

=3750m²

Cost of reaping 50m² of the field = 15 Rupees

Cost of reaping 1m² of the field = 15/50

=3/10= 0.3 Rupees

cost of reaping the whole field = 0.3×3750

=1125 Rupees

PLEASE MARK ME AS THE BRAINLIEST!!! AND THIE QUESTION SHOULD BE MINIMUM OF 10 POINTS!

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