The length and breadth of a rectangular field are in the ratio3:2.If the area of the field is 4056 cm²,Find the length and breadth of the field.
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Let the length and breadth be = 3x and 2x
★ ![\sf { Area\: of\: a \:rectangle = length \times breadth } \sf { Area\: of\: a \:rectangle = length \times breadth }](https://tex.z-dn.net/?f=+%5Csf+%7B+Area%5C%3A+of%5C%3A+a+%5C%3Arectangle+%3D+length+%5Ctimes+breadth+%7D+)
» 4056 = 3x × 2x
» 4056 = 6x²
» x² = 576
» x = 24
★ ![\sf { Perimeter \: of \: a \:rectangle = 2(length+breadth) } \sf { Perimeter \: of \: a \:rectangle = 2(length+breadth) }](https://tex.z-dn.net/?f=+%5Csf+%7B+Perimeter+%5C%3A+of+%5C%3A+a+%5C%3Arectangle+%3D+2%28length%2Bbreadth%29+%7D)
» Perimeter = 3x + 2x
» Perimeter = 5x
» Perimeter = 5(24)
» Perimeter = 120
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