Environmental Sciences, asked by Dev31234, 4 months ago

The length and breadth of a rectangular field are in the ratio 9 : 5. If the area of the field is 14580 square metre, find the cost of surrounding the field with a fence at the rate of Rupees 3.25 per metre?​

Answers

Answered by MoodyCloud
72

Given:-

  • Length and breadth of rectangular field are in ratio 9:5.
  • Area of field is 14580 m sq.

To find:-

  • Cost of fencing the surrounding of field.

Solution:-

Let, Length of rectangular field be 9x.

And Breadth of rectangular field be 5x.

 \boxed{ \sf \bold{Area \: of \: rectangle = length \times breadth}}

Put area, length and breadth of rectangular field in formula:

   \sf \longrightarrow 14580 = 9x \times 5x

 \sf \longrightarrow 14580 = 45 {x}^{2}

 \sf  \longrightarrow  \dfrac{14580}{45}  =  {x}^{2}

 \sf \longrightarrow 324 =  {x}^{2}

 \sf \longrightarrow x =  \sqrt{324}

 \sf \longrightarrow  \green{ \boxed{ \sf \bold{x = 18}} \star}

We have taken,

Length = 9x = 9×18 = 162 m

Breadth = 5x = 5×18 = 90 m.

 \boxed{ \sf \bold{Perimeter\: of \: rectangle = 2(length + breadth)}}

Put length and breadth,

 \sf \longrightarrow 2 \times (162 + 90)

 \sf \longrightarrow 324 + 180

\sf \longrightarrow \red{ \boxed{ \sf \bold{504}} \star}

Perimeter of rectangular field is 504 m.

  • We know fence and perimeter are same.

So, Fence of rectangular field is 504 m.

1 m = Rs 3.25

For 504 m -

\sf \longrightarrow 504 \times 3.25

\sf \longrightarrow \purple{ \boxed{ \sf \bold{1638}} \bigstar}

Therefore,

Cost for fencing rectangular field is Rs. 1638 .


amitkumar44481: Great :-)
Answered by Anonymous
90

Answer:

 \huge \bf \: Given

  • Length and breadth of a rectangular field = 9:5
  • Area of field = 14580 m²
  • Cost of fence per metre = ₹3.25

 \huge \bf \: To \: find \:

Total cost

 \huge \bf \: Solution

Let the length be 9x and Breadth be 5x

 \sf \implies \: 14580 = 9x \times 5x

 \sf \implies \: 14580 = 45 {x}^{2}

 \sf \implies \:  \dfrac{14580}{45}  =  {x}^{2}

 \sf \implies \: 324 =  {x}^{2}

 \sf \implies \: x \: =  \sqrt{} 324

 \small \bf \: x \:  = 18

Now,

Finding length and breadth

 \sf \: 9x = 9(18) = 162

 \sf 5x = 5(18) = 90

Now,

Finding perimeter

  \fbox {Perimeter \:  = 2(l + b)}

 \sf \implies \: Perimeter \:  = 2(162 + 90)

 \sf \implies Perimeter \:  = 2(252)

 \fbox {Perimeter = 504 \: m}

Now,

Finding total cost

 \sf \: Cost \: of \: fence \:  1 \: m=  3.25

 \sf \: Cost \: of \: fence \: 504 \: m \: = 1638

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