Math, asked by hariba762, 12 hours ago

The Length and breadth of a rectangular field are in the ratio 9:5. If the area of the field is 14850 square metre. Find the cost of Surrounding the field with a fence at the rate of 2 3.25 per mer​

Answers

Answered by SavageBlast
20

Appropriate Question:-

The Length and breadth of a rectangular field are in the ratio 9:5. If the area of the field is 14850 square metre. Find the cost of Surrounding the field with a fence at the rate of 3.25 per square metre.

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Given:-

  • Length and breadth of a rectangular field are in the ratio 9:5.

  • Area of the Field is 14,850m².

To Find:-

  • Cost of Surrounding the field with a fence at the rate of 3.25 per square metre.

Formula Used:-

  • {\boxed{\bf{\red{Area\:of\: Rectangle=Length \times Breadth}}}}

  • {\boxed{\bf{\red{Perimeter\:of\: Square=2(l+b)}}}}

Solution:-

Let the length and breadth be 9x and 5x.

Firstly,

\sf :\implies\:Area\:of\: Field= Length \times Breadth

\sf :\implies\:14,850= 9x \times 5x

\sf :\implies\:14,850= 45x^2

\sf :\implies\:x^2=\dfrac{14,850}{45}

\sf :\implies\:x^2=330

\sf :\implies\:x=\sqrt{330}

  • Length = 9x = \bf 9\sqrt{330}m

  • Breadth = 5x = \bf 5\sqrt{330}m

Now,

\sf :\implies\: Perimeter\:of\: Field=2(l+b)

\sf :\implies\: Perimeter\:of\: Field=2(9\sqrt{300}+5\sqrt{300})

\sf :\implies\: Perimeter\:of\: Field=2 \times 14\sqrt{300}

\sf :\implies\: Perimeter\:of\: Field=28\sqrt{300}m

Finally,

Cost of Surrounding the field with a fence at the rate of 3.25 per square metre:-

\sf :\implies\: 28\sqrt{300}\times 3.25

\sf :\implies\: 28\times 17.32\times 3.25

\sf :\implies\: Rs. 1,576.12

Hence, Cost of Surrounding the field with a fence at the rate of 3.25 per square metre is Rs. 11,576.12.

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